100 lines
3.0 KiB
Go
100 lines
3.0 KiB
Go
// ODEAdamsEX
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/*
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------------------------------------------------------
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作者 : Black Ghost
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日期 : 2018-12-13
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版本 : 0.0.0
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------------------------------------------------------
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四步Adams外推公式,显式、线性
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理论:
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h
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y_(n+1) = yn + ----(55f(xn,yn) - 59f(x_(n-1),y_(n-1)) +
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24
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37f(x_(n-2),y_(n-2)) - 9f(x_(n-3),y_(n-3)))
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参考 李信真, 车刚明, 欧阳洁, 等. 计算方法. 西北工业大学
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出版社, 2000, pp 200-201.
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------------------------------------------------------
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输入 :
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fun 被积分函数
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x0 初值
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xend 积分终止点
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fn 方程个数
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n 迭代次数
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输出 :
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sol 解矩阵
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err 解出标志:false-未解出或达到步数上限;
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true-全部解出
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------------------------------------------------------
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*/
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package goNum
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// ODEAdamsEX 四步Adams外推公式,显式、线性,单个方程
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func ODEAdamsEX(fun func(Matrix, int) float64, x0 Matrix, xend float64, fn, n int) (Matrix, bool) {
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/*
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四步Adams外推公式,显式、线性,单个方程
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输入 :
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fun 被积分函数
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x0 初值
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xend 积分终止点
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fn 方程个数
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n 迭代次数
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输出 :
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sol 解矩阵
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err 解出标志:false-未解出或达到步数上限;
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true-全部解出
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*/
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//判断方程个数是否对应初值个数
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if x0.Rows != fn+1 {
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panic("Error in goNum.ODEAdamsEX: Quantities of x0 and fn+1 are not equal")
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}
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sol := ZeroMatrix(fn+1, n+1)
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h := (xend - x0.GetFromMatrix(0, 0)) / float64(n)
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//把初值赋给sol
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for i := 0; i < fn+1; i++ {
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sol.SetMatrix(i, 0, x0.Data[i])
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}
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//前三个使用RK44计算,不包括已有的初值点
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xendRK := x0.GetFromMatrix(0, 0) + 3.0*h
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solRK, errRK := RK44(fun, x0, xendRK, fn, 3)
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if errRK != true {
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panic("Error in goNum.ODEAdamsEX: RK44 solving error")
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}
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//传递RK44计算的结果到sol
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for k := 0; k < fn+1; k++ { //fn个方程,fn+1个参数
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for i := 1; i < 4; i++ { //三个结果
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sol.SetMatrix(k, i, solRK.GetFromMatrix(k, i))
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}
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}
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//Adams外推公式, 4(即n+1)需要3,2,1,0四个
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for i := 4; i < n+1; i++ {
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sol.SetMatrix(0, i, sol.GetFromMatrix(0, i-1)+h) //xi
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//临时初值
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xyn := ZeroMatrix(fn+1, 1)
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xyn_1 := ZeroMatrix(fn+1, 1)
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xyn_2 := ZeroMatrix(fn+1, 1)
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xyn_3 := ZeroMatrix(fn+1, 1)
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for j := 0; j < fn+1; j++ {
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xyn.Data[j] = sol.GetFromMatrix(j, i-1)
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xyn_1.Data[j] = sol.GetFromMatrix(j, i-2)
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xyn_2.Data[j] = sol.GetFromMatrix(j, i-3)
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xyn_3.Data[j] = sol.GetFromMatrix(j, i-4)
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}
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//计算
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for j := 0; j < fn; j++ { //不包含xi的其他参数
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temp0 := 55.0*fun(xyn, j) - 59.0*fun(xyn_1, j) + 37.0*fun(xyn_2, j) - 9.0*fun(xyn_3, j)
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temp0 = xyn.Data[j+1] + temp0*h/24.0
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sol.SetMatrix(j+1, i, temp0) //yi
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}
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}
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return sol, true
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}
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