fixed dependencies
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85
vendor/github.com/nuknal/goNum/SimpleIterate.go
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85
vendor/github.com/nuknal/goNum/SimpleIterate.go
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// SimpleIterate
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/*
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------------------------------------------------------
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作者 : Black Ghost
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日期 : 2018-11-01
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版本 : 0.0.0
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------------------------------------------------------
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简单迭代求解类x=g(x)方程的解 xn+1=g(xn)
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理论:
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1. g(x)在区间[a, b]可导;
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2. 当xE[a, b],g(x)E[a, b];
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3. 对于任意xE[a, b],|g‘(x)| <= L < 1
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线性收敛
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则求解所得的根xn与真实根xr的的误差:
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L^n
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|xn-xr| <= ----- |x1-x0|
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1-L
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------------------------------------------------------
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输入 :
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fn g(x)函数,定义为等式右侧部分,左侧为x
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a, b 求解区间
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c 求解初值
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N 步数上限
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tol 误差上限
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输出 :
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sol 解值
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err 解出标志:false-未解出或达到步数上限;
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true-全部解出
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------------------------------------------------------
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*/
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package goNum
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import (
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"math"
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)
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// SimpleIterate 简单迭代求解类x=g(x)方程的解 xn+1=g(xn)
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func SimpleIterate(fn func(float64) float64, a, b, c float64,
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N int, tol float64) (float64, bool) {
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/*
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简单迭代求解类x=g(x)方程的解 xn+1=g(xn)
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输入 :
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fn g(x)函数,定义为等式右侧部分,左侧为x
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a, b 求解区间
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c 求解初值
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N 步数上限
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tol 误差上限
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输出 :
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sol 解值
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err 解出标志:false-未解出或达到步数上限;
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true-全部解出
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*/
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var sol float64
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var err bool = false
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// 判断端点和初值是否为所求之解
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switch {
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case math.Abs(fn(a)-a) < tol:
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sol = a
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err = true
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return sol, err
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case math.Abs(fn(b)-b) < tol:
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sol = b
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err = true
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return sol, err
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case math.Abs(fn(c)-c) < tol:
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sol = c
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err = true
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return sol, err
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}
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//求解
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sol = fn(c)
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for i := 0; i < N; i++ {
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if (math.Abs(sol - c)) < tol {
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err = true
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return sol, err
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}
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c = sol
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sol = fn(c)
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}
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return sol, err
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}
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